The specific heat capacity of iron is 0.45 j/g oC. how many joules of energy are needed to warm 1.3100000000000001 g of iron from 20.00oC to 29.00 oC ?
To calculate the amount of energy needed to warm a substance, you can use the formula:
Q = mcΔT
Where:
Q is the energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g·°C)
ΔT is the change in temperature (in °C)
Let's plug in the given values into the formula:
m = 1.3100000000000001 g
c = 0.45 J/g·°C
ΔT = 29.00 °C - 20.00 °C = 9.00 °C
Q = (1.3100000000000001 g) * (0.45 J/g·°C) * (9.00 °C)
Now let's calculate the answer:
Q = 5.9035 J
Therefore, approximately 5.9035 joules of energy are needed to warm 1.3100000000000001 g of iron from 20.00°C to 29.00°C.