IS THIS CORRECT NOW.
solve by using the quadratic formula.
x^2 = -5-5
My answer:
x = (-5 +- SQRT (5))/(2)
I don't see any x term, so b is zero.
sorry it suppost to read that first
-5x-5
To solve the equation -5x - 5 = 0 using the quadratic formula, we need to rewrite the equation in the form ax^2 + bx + c = 0, where a, b, and c are the coefficients.
In this case, the equation is already in the required form, with a = -5, b = -5, and c = 0. Now we can apply the quadratic formula:
x = (-b +- sqrt(b^2 - 4ac))/(2a)
Substituting the values of a, b, and c into the formula, we get:
x = (-(-5) +- sqrt((-5)^2 - 4(-5)(0))) / (2(-5))
x = (5 +- sqrt(25))/(-10)
Simplifying further, we have:
x = (5 +- 5)/(-10)
x = (5 + 5)/(-10) or x = (5 - 5)/(-10)
x = 10/(-10) or x = 0/(-10)
Finally, we simplify our solutions:
x = -1 or x = 0
So, the solutions to the equation -5x - 5 = 0, when solved using the quadratic formula, are x = -1 and x = 0.