Solve the following equation
5(z-4)-z=4z-20
4
-4
Infinitely many solutions
No solution
I had found that the answer was 0=0, but what does that mean? I’m confused. Thank you in advance.
There are infinitely many solutions, C is correct.
I think the answer is C. if anyone could help :-) no rush
In solving equation, if your variable drops and and you get:
1. a statement which is true, such as 0=0 , or 5=5, then there will be an infinite number of solutions.
2. a statement which is false, such as 0=8 , or 23 = 67 , then there is no solution to the equation
So I redid my math, and I replaced the x with 4. In the end on both sides I got -4 as the answer. If I did -4, there was no answer. So does that mean the answer is 4? It’s not asking what x is, but maybe it is? I know for a fact that B and D are not correct, but is it A or C?
So... idk what the answer is... perfect
To solve the equation 5(z-4)-z=4z-20, we can start by expanding the brackets:
5z - 20 - z = 4z - 20
Next, we can simplify the equation by combining like terms. Let's gather all the z terms on one side of the equation and the constant terms on the other side:
(5z - z) - 4z = -20 + 20
Simplifying further:
4z - 4z = 0
The equation simplifies to:
0 = 0
So, the answer to the equation is 0=0.
When we get 0=0 as the answer, it means that the equation is an identity. An identity is a mathematical statement that holds true for all possible values of the variable(s) involved. In other words, it means that any value of z we substitute into the equation will make both sides equal.
In this case, it means that no matter what value we choose for z, both sides of the equation will always be equal to zero. Therefore, this equation has infinitely many solutions.