Calculate the momentum of a particle which has a dedicated broglie lambda of 0.1 nm.
https://formulas.tutorvista.com/physics/de-broglie-wavelength-formula.html
To calculate the momentum of a particle, we can use the de Broglie wavelength (λ) and Planck's constant (h). The de Broglie wavelength is related to the momentum of a particle through the following equation:
λ = h / p,
where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the momentum of the particle.
Now, we can rearrange the equation to solve for the momentum:
p = h / λ.
Given that the de Broglie wavelength (λ) is 0.1 nm (0.1 x 10^-9 m), we can directly substitute these values into the equation:
p = (6.626 x 10^-34 J s) / (0.1 x 10^-9 m).
By performing the calculation, we find:
p = 6.626 x 10^-25 kg m/s.
Therefore, the momentum of the particle is 6.626 x 10^-25 kg m/s.