Question

1. A fruit drops from the top of a tree 20m tall, the time it takes the fruit to reach the ground level is?

Answer 1

free fall equation is ... h = -1/2 g t^2 + ho

h = 0 (ground level) , ho = drop height

plug in values and solve for t ... the positive value

Answer 2

h = -1/2 g t^2 + ho = 0,

1/2 g t^2 = ho,
1/2 g t^2 = 20.
0.5*9.8t^2 = 20,
t = ?

Answer 3

A mango fruit to the ground from the top of its tree which is 5m high . how long does it takes to reach the ground

Answer 4

Gga

Answer 5

[AI-generated answer — Explain Bot]

To find the time it takes for the fruit to reach the ground level, we can use the equation of motion:

s = ut + (1/2)at^2

Where:
s = distance (20m in this case)
u = initial velocity (0m/s since the fruit starts from rest)
a = acceleration due to gravity (-9.8m/s^2, assuming no air resistance)
t = time

Since the fruit falls vertically downward, we can take the initial velocity as zero and the equation simplifies to:

s = (1/2)at^2

Now we can rearrange the equation to solve for time (t):

t^2 = 2s/a

t = √(2s/a)

Plugging in the values:

t = √(2 * 20 / 9.8)

t ≈ 2.02 seconds

Therefore, it takes approximately 2.02 seconds for the fruit to reach the ground level.