the SMALLEST of 3 consecutive numbers is n. the average of these 3 numbers is:
a. (n+2)/3
b. n+1
c. 3(n+1)/2
d. 3n/3
is b the correct answer ?
Yes (both mean and median)
(n + n+1 + n+2)/3 = (3n + 3)/3 = n+ 1
Sorry I am so late to answer I have been in the Hospital😷😷 latley
yes it is correct
I have cancer so I have been on and off chemo treatment and I just fineshed for the day so I am feeling better but I have been throwing up A LOT. Also I am tired and my spelling is not so good.
😴😴 I am tired so I will sleep now
To find the average of three consecutive numbers starting from the smallest number, you can use the formula:
Average = (Smallest Number + Middle Number + Largest Number) / 3
Let's denote the smallest number as "n". The three consecutive numbers would be n, n+1, and n+2.
Using the formula, we can calculate the average:
Average = (n + (n+1) + (n+2)) / 3
Simplifying the expression:
Average = (3n + 3) / 3
We can further simplify by dividing both the numerator and denominator by 3:
Average = (3/3) * (n + 1)
Average = n + 1
Therefore, the correct answer is b) n+1.