bob accidently falls out of a helicopter that is traveling horizonally at 160m/s. he plunges into the water below 4s later. assuming there is no air resistance, what is the horizontal distance he travels while falling
I would use
distance straight down to the water = 1/2(g)*t^2 which will allow you to determine how high Bob was when he fell out of the plane.
Then distance = rate x time
You know rate and you know time, calculate distance traveled horizontally. Check my thinking.
To find the horizontal distance Bob travels while falling, we can use the formula:
distance = velocity x time
In this case, the velocity is the horizontal velocity of the helicopter, which is 160 m/s. The time is the duration of the fall, which is 4 seconds.
So, the horizontal distance Bob travels while falling is:
distance = 160 m/s x 4 s
Now, let's calculate the answer:
distance = 640 meters
Therefore, Bob travels a horizontal distance of 640 meters while falling.