AHH I had made a new question saying the same as in this one but i had not saved it to my browser bar, so here we are again!
Hi ms.sue, :'D
You roll a number cube twice. find P(Even, then not 2). Write the probability as a fraction in simplest form.
I don't have a answer because i didn't understand the question.
Hello! I'd be happy to help you understand the question and find the answer.
In this problem, you're rolling a number cube (often referred to as a fair six-sided die) twice. Each time you roll the cube, you can get a number from 1 to 6. To find the probability of certain outcomes, we need to determine the total possible outcomes and the favorable outcomes.
Let's break down the question:
P(Even, then not 2)
We have two conditions here:
1. Even: The first roll must result in an even number.
2. Not 2: The second roll must not result in a 2.
Now, let's figure out the total possible outcomes and favorable outcomes step by step:
Total possible outcomes for each roll = 6 (since there are six sides on a number cube)
Favorable outcomes for being even = 3 (2, 4, 6)
Favorable outcomes for not being 2 = 5 (1, 3, 4, 5, 6)
To find the probability of both events happening, we multiply the probabilities of each condition occurring. So:
P(Even, then not 2) = (favorable outcomes for being even / total possible outcomes) * (favorable outcomes for not being 2 / total possible outcomes)
P(Even, then not 2) = (3/6) * (5/6)
Simplifying the fraction, we have:
P(Even, then not 2) = 15/36
So, the probability of rolling an even number and then rolling a number that is not 2 is 15/36, which can't be simplified further.
I hope this explanation helps you understand the question and how to find the answer! If you have any more questions, feel free to ask.