Write the function in terms of the cofnction with an acute angle.
tan 18degrees
A. sec18deg
B. cot18deg
C. cot72deg
D. cot108deg
find a solution for the equation.
sin(2theta+20deg) = cos(3theta-5deg)
thnkks:))
draw a right triangle. Let A and B be the acute angles. Isn't tanA=ctnB, so
tanA=ctn(90-A)
thnks..can you help me with the second one
find a solution for the equation.
sin(2theta+20deg=cos(3theta-5deg)
:)
To write tan 18 degrees in terms of a function with an acute angle, we can use the following trigonometric identity:
tan(x) = cot(90° - x)
Therefore, we have:
tan 18° = cot(90° - 18°) = cot 72°
So, the answer is option C: cot 72°.
For the equation sin(2theta + 20°) = cos(3theta - 5°), we can use some trigonometric identities to simplify it and find a solution.
First, let's convert the angles in terms of a single variable (theta):
2theta + 20° = theta - (3theta - 5°)
Simplifying the equation:
2theta + 20° = -2theta + 5°
Moving all terms to one side of the equation:
2theta + 2theta = 5° - 20°
4theta = -15°
Dividing both sides by 4:
theta = -3.75°
So, a solution to the equation sin(2theta + 20°) = cos(3theta - 5°) is theta = -3.75°.