On Wednesday, a local hamburger shop sold a combined total of
408
hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Wednesday?
On Saturday, a local hamburger shop sold a combined total of 408 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold. How many hamburgers were sold on Saturday?
Let's assume the number of hamburgers sold is 'x'.
According to the given information, the number of cheeseburgers sold is three times the number of hamburgers sold.
Therefore, the number of cheeseburgers sold is 3x.
The combined total of hamburgers and cheeseburgers sold is 408.
So, we can write the equation:
x + 3x = 408
Simplifying the equation:
4x = 408
Dividing both sides of the equation by 4:
x = 408/4
x = 102
Therefore, 102 hamburgers were sold on Wednesday.
To find the number of hamburgers sold on Wednesday, we need to set up a system of equations based on the given information.
Let's assume the number of hamburgers sold is H and the number of cheeseburgers sold is C.
According to the problem, "The number of cheeseburgers sold was three times the number of hamburgers sold." This can be written as:
C = 3H
We also know that the "combined total of 408 hamburgers and cheeseburgers" were sold. This can be written as:
H + C = 408
Now we can solve the system of equations simultaneously to find the value of H.
Substituting the value of C from the first equation into the second equation:
H + 3H = 408
4H = 408
H = 408/4
H = 102
Therefore, the hamburger shop sold 102 hamburgers on Wednesday.
h + 3h = 408
4h = 408
h = 102