Glucose( C6H12O6) is produced by photosynthese.
For every kilo of water the plant takes in ,how much glucose can it make ?
I done the balanced equation wich is (I think)
6H2O+6CO2 = C6 H12 3O6
After that I get a ratio of 108/372 wich give me a tota of 3444 grammes of glucose Am I right ?
You're almost correct with the balanced equation for photosynthesis:
6H2O + 6CO2 = C6H12O6 + 6O2
For every 6 moles of water the plant takes in, it produces 1 mole of glucose.
A kilo of water = 1000g
Number of moles of water = 1000/18 = 55.55
Number of moles of glucose produced = 55.55/6 = 13.88
Mass of glucose = Number of moles x Molecular Mass
= 13.88 x 180
= 2500g
= 2.5kg
thanks
To determine the amount of glucose produced by a plant in relation to the water it takes in, you need to understand the stoichiometry of the balanced chemical equation for photosynthesis.
The balanced equation you provided is slightly incorrect. The correct equation for photosynthesis is:
6 CO2 + 6 H2O -> C6H12O6 + 6 O2
This equation shows that six molecules of carbon dioxide (CO2) and six molecules of water (H2O) are converted into one molecule of glucose (C6H12O6) and six molecules of oxygen (O2).
To find out how much glucose can be produced from a kilogram of water, we need to calculate the molar mass of water (H2O) and glucose (C6H12O6), and then use that information to find the molar ratio.
The molar mass of water (H2O) is given by:
2(atomic mass of hydrogen) + atomic mass of oxygen
= 2(1.008 g/mol) + 16.00 g/mol
= 18.016 g/mol
The molar mass of glucose (C6H12O6) is given by:
6(atomic mass of carbon) + 12(atomic mass of hydrogen) + 6(atomic mass of oxygen)
= 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00 g/mol)
= 180.18 g/mol
Now, we can set up the molar ratio:
1 mol glucose / 6 mol water = 180.18 g glucose / 6(18.016 g) water
Simplifying:
1 mol glucose / 6 mol water = 180.18 g glucose / 108.09 g water
Now, to find the amount of glucose produced from 1 kg (1000 g) of water, we use the molar ratio:
Amount of glucose = (1000 g water) * (180.18 g glucose / 108.09 g water)
Calculating:
Amount of glucose = 1000 * 180.18 / 108.09
= 1653.25 g
Therefore, from 1 kg of water, the plant can produce approximately 1653.25 grams (or 1.65 kg) of glucose, not 3444 grams as you mentioned earlier.