# Show that if the diagonals of a quadrilateral are perpendicular, then its area is half the product of the diagonals.

What kind of drawing do I do? And how doI solve this? Thank you!

## Draw a long line, mark a point O on the line

mark one side of O length a

mark the other side length b

the total length is then (a+b)

Draw a short line through O perpendicular to the first one

Draw a short line through O, perpendicular to the long one .

Lengths c and d, total length (c+d)

Those are your two diagonals.

now connect the tips of those lines and you have your quadrilateral.

Now look at the four triangles

area is

(1/2)ac + (1/2)ad + (1/2)bc + (1/2)bd

now what is (1/2)(a+b)(c+d) ?

(1/2)( ac + ad + bc + bd)

:) look familiar?

## To prove that if the diagonals of a quadrilateral are perpendicular, then its area is half the product of the diagonals, you can follow these steps:

1. Draw a quadrilateral (ABCD) on a piece of paper.

2. Label the diagonals as AC and BD, where segment AC intersects segment BD at point O, forming right angles (∠AOC and ∠BOD).

3. Draw altitude lines from point O onto sides AB, BC, CD, and DA. Label these altitudes as h1, h2, h3, and h4, respectively.

4. Using the properties of perpendicular lines, you can observe that ∠AOC and ∠BOD are right angles, which means that triangles AOB and COD are right triangles.

5. The area of a triangle is given by the formula: Area = 1/2 * base * height.

6. Apply this formula to triangles AOB and COD to find their respective areas. The base of triangle AOB is diagonal AC, and the height is h1, which is the altitude from point O to side AB. Similarly, the base of triangle COD is diagonal AC, and the height is h3, which is the altitude from O to side CD.

7. Calculate the areas of triangles AOB and COD using the formula: Area = 1/2 * base * height.

8. Add the areas of triangles AOB and COD together to get the total area of quadrilateral ABCD.

9. Simplify the expression for the total area to show that it is equal to 1/2 times the product of the diagonals AC and BD.

## To show that if the diagonals of a quadrilateral are perpendicular, then its area is half the product of the diagonals, you will need to draw the quadrilateral and label its diagonals. I would suggest drawing a simple quadrilateral, such as a rectangle or a kite, to make the visualization easier.

Here are the steps to solve this:

1. Draw a quadrilateral ABCD, where AB and CD are the diagonals and they intersect at point E, forming right angles.

2. Label the length of AB as d1 and the length of CD as d2.

3. Draw the perpendicular bisectors of AB and CD. Let them intersect at point O, which will be the center of the quadrilateral (the point equidistant from all the vertices).

4. Label the lengths of OE and OD as h1 and h2, respectively, where h1 represents the distance from O to the midpoint of AB, and h2 represents the distance from O to the midpoint of CD.

5. Recall that the area of a quadrilateral can be calculated using the formula: Area = (1/2) * product of the diagonals * sine of the angle between them.

6. In this case, since the diagonals are perpendicular, the angle between them is 90 degrees, and the sine of 90 degrees is 1.

7. Substitute the values into the formula: Area = (1/2) * d1 * d2 * 1 = (1/2) * d1 * d2.

8. Therefore, the area of the quadrilateral is half the product of the diagonals.

By following these steps and visually representing the quadrilateral, you can clearly understand and prove that if the diagonals of a quadrilateral are perpendicular, the area is indeed half the product of the diagonals.