# A watertight car is submerged under water. What force is required to open a door of area 1.04 m2 if the average depth of water at the door is 1.56 m?

## To determine the force required to open the door of a watertight car submerged underwater, we can use the concept of fluid pressure.

The formula for fluid pressure is given by:

Pressure = Density × Gravitational acceleration × Depth

Here, the density of water is constant and equal to 1000 kg/m3, and the gravitational acceleration is 9.8 m/s2.

Step 1: Calculate the pressure exerted by the water at the door:
Pressure = (Density) × (Gravitational acceleration) × (Depth)
= (1000 kg/m3) × (9.8 m/s2) × (1.56 m)
≈ 15288 Pa

Step 2: Determine the force required to open the door:
Force = Pressure × Area
= (15288 Pa) × (1.04 m2)
≈ 15905.92 N

Therefore, the force required to open the door of area 1.04 m2, when submerged with an average depth of water of 1.56 m, is approximately 15905.92 Newtons.

## To calculate the force required to open the door of a watertight car submerged under water, we need to consider the pressure exerted by the water on the door.

The pressure exerted by a fluid is given by the formula:
Pressure = Density x Gravity x Depth

In this case, the fluid is water, so we can use the density of water, which is approximately 1000 kg/m3, and the acceleration due to gravity, which is 9.8 m/s2.

First, we need to calculate the pressure exerted by the water on the door:

Pressure = Density x Gravity x Depth
= 1000 kg/m3 x 9.8 m/s2 x 1.56 m
≈ 15288 Pa

Since pressure is force per unit area, we can calculate the force by multiplying pressure by the area of the door:

Force = Pressure x Area
= 15288 Pa x 1.04 m2
≈ 15922 N

Therefore, approximately 15922 Newtons of force is required to open the door of the watertight car under the given conditions.