# A ball of mass 4 Kg falls to the floor; it lands with a speed of 6 m/s.it bounces off with same speed.show that its momentum has changed by 48 kg m/s?

## initial momentum = -4 * 6

final momentum = +4*6

change in momentum = +24 - (-24 ) = +48

## A ball of Mass 4kg falls to floor; it lands with a speed of 6m/s. It bounces off with the same speed . show that momentum has changed by 48kgm/s

## Physics

## initial momentum= m×v final momentum= -m×v

=4×6 =-4×6

=24kgm/s =-24kgm/s

change in momentum

=initial momentum - final momentum

= 24-(-24)=48kgm/s

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## A ball of Mass 4kg falls to floor; it lands with a speed of 6m/s. It bounces off with the same speed . show that momentum has changed by 48kgm/s

## The initial momentum is negative 4 times 6

And then the final momentum is positive 4 times 6

So the change in momentum will be

+24-(-24) which is equal to 48kgm|s