Here's the question I'm having trouble with:
Tell how you would identify the intercepts for the graph of the equation:
3x + 6y = 18
I'm not exactly sure how you would find the intercepts from this equation.
Thanks!
15 years ago
15 years ago
Yes! I see, I didn't really think of it that way until after I posted the message. Thank you!
15 years ago
lol wow i actually helped ?!
i was just guessing .. im only in grade 11 anyways
15 years ago
If they are written in the form you have, it is often very easy to find
remember to find the x-intercept you let y=0 and to
find the y-intercept you let the x=0
of course letting some variable equal to zero makes that term disappear.
so to let x=0, block out the x term with your little finger, what do you see?
6y = 18, then y = 3
for the x-intercept, block out the y-term with your little finger and ...
x = 6
this works really neat if the x and y coefficients both divide evenly into the constant
7 months ago
To identify the intercepts for the graph of the equation 3x + 6y = 18, you can use a method called "setting x or y as zero."
First, let's find the x-intercept. To find this, we set y equal to zero in the equation and solve for x. So, we substitute 0 for y and solve for x:
3x + 6(0) = 18
3x + 0 = 18
3x = 18
x = 18/3
x = 6
Therefore, the x-intercept is (6, 0), which means the graph crosses the x-axis at the point (6, 0).
Next, let's find the y-intercept. To find this, we set x equal to zero in the equation and solve for y. So, we substitute 0 for x and solve for y:
3(0) + 6y = 18
0 + 6y = 18
6y = 18
y = 18/6
y = 3
Therefore, the y-intercept is (0, 3), which means the graph crosses the y-axis at the point (0, 3).
In summary, the x-intercept is (6, 0) and the y-intercept is (0, 3) for the graph of the equation 3x + 6y = 18.