Evaluate this pricewise function at x=-4 and x=4.
f(x)={x^2, if x less than or equal to -4
{x^3, if -4 less than x less than or equal to1
{square root x, if x greater than 1
(I wanted to use symbols but I didn't have the greater than or less than equal to symbols so I used words, I hope you guys underhand the problem and is still able to help solve this with me. Because I seriously need help solving this. Thank you in advance)
Combine the left carat key (<) with the "alt option" key to get the "less than or equal" symbol (≤).
To evaluate the pricewise function at x = -4 and x = 4, we need to plug in these values into the respective cases defined in the function.
Given:
f(x) = {
x^2, if x ≤ -4
x^3, if -4 < x ≤ 1
√x, if x > 1
}
Let's start by evaluating f(x) at x = -4:
Since -4 ≤ -4, we use the first case of the function.
Substituting x = -4 into the case, we have:
f(-4) = (-4)^2 = 16
Now, let's evaluate f(x) at x = 4:
Since 4 > 1, we use the third case of the function.
Substituting x = 4 into the case, we have:
f(4) = √4 = 2
Therefore, evaluating the pricewise function at x = -4 gives us f(-4) = 16, and evaluating it at x = 4 gives us f(4) = 2.