Let n represent the number of similar resistors in a circuit. Each resistor has a resistance of r. When the resistors are connected in parallel the circuit has a total resistance of R. What would the total resistance of the circuit be if the resistors were instead connected in series?
parallel= resistance= R=rEach/n
series= n*reach=n*n*R= n^2 R
1/R = n/r
so
R = r/n
in series R = n r
To find the total resistance of the circuit when the resistors are connected in series, we need to add up the resistances of all the resistors.
If there are n similar resistors connected in series, the total resistance would be:
R_series = n * r
So, the total resistance of the circuit when the resistors are connected in series is n times the resistance of a single resistor.
To calculate the total resistance of resistors connected in series, we need to add up the individual resistances.
Since there are 'n' similar resistors with a resistance of 'r' each, the total resistance of 'n' resistors connected in series would be:
Total resistance (series) = resistance of one resistor + resistance of another resistor + ... + resistance of the nth resistor
In this case, since all the resistors are similar with a resistance of 'r', the total resistance can be calculated as:
Total resistance (series) = n * r
So, if the resistors were connected in series, the total resistance of the circuit would be 'n' times the resistance of each individual resistor.