Temperature at 5pm was 0degree c.if temperature is dropping2degree c per hour what was the temperature 9hours ago?
Temperature at
5pm = 0degreec. Drop in temperature =2degree c per hour. 0degreec - 2degreec = - 2degreec.temperature 9 hrs ago= -2degreec - 0degreec = 2degreec
if dropping 2°/hr, then 9 hours ago, it was 2*9 = 18° higher than it is now.
To find the temperature 9 hours ago, we need to subtract the temperature drop from the current temperature.
Since the temperature is dropping 2 degrees Celsius per hour, we can calculate the temperature drop over 9 hours by multiplying the temperature drop per hour by the number of hours.
Temperature drop over 9 hours = 2 degrees Celsius/hour * 9 hours = 18 degrees Celsius
Now, we subtract the temperature drop from the current temperature to find the temperature 9 hours ago:
Temperature 9 hours ago = 0 degrees Celsius - 18 degrees Celsius = -18 degrees Celsius
Therefore, the temperature 9 hours ago was -18 degrees Celsius.