The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant the first time and a vowel the second time if the spinner is spun twice
My spinner has 3 parts, N E and U
A:2/3
B:2/9
C:3/4
D:5/9
I think the answer is A. thank you
not correct for dis yeaar
It is pointless to look at this website for answers to tests, as the test are given random to each person!!!
my question said my spinner has equal parts not four equal parts. it is 3.
You are right!
I can't draw a tree diagram on here, but I can show the math.
Prob(consonant on first spin)
= 1/3
Prob(vowel on 2nd spin)
= 2/3
prob(event as stated)
= (1/3)(2/3)
= 2/9
KArl like trains
Gamer girl, the tests are random for everyone so the answers won't be accurate
5 months later... Still got the whole test?
thank you
happy b-day
I gotchu are you sure? Im really struggling :/
8*
The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.
the spinner contains, N, E, and U
Here's a tree diagram to represent the possible outcomes of spinning the spinner twice:
```
/-- N -- N
--|
\-- N -- E
--|
/-- E -- N
--|
\-- E -- E
--|
/-- U -- N
--|
\-- U -- E
```
There are 3 possible consonants (N and U) and 3 possible letters in all. Therefore, the probability of getting a consonant on the first and second spins is:
P(consonant on first spin) = 2/3
P(consonant on second spin given consonant on first spin) = 2/3
Now, we use the multiplication rule to find the probability of getting a consonant both times:
P(consonant on first spin and consonant on second spin) = P(consonant on first spin) x P(consonant on second spin given consonant on first spin)
= (2/3) x (2/3)
= 4/9
Therefore, the probability of the spinner landing on a consonant both times is 4/9.
An ice cream shop offers 5 different flavors of ice cream and 12 different toppings. How many choices are possible for a single serving of ice cream with one topping?
We can use the multiplication principle to find the total number of choices for a single serving of ice cream with one topping.
There are 5 different flavors of ice cream and 12 different toppings.
Using the multiplication principle, we can multiply the number of choices for each part to find the total number of choices:
Number of choices for ice cream = 5
Number of choices for toppings = 12
Total number of choices = 5 x 12 = 60
Therefore, there are 60 possible choices for a single serving of ice cream with one topping.
Tamara likes to mix and match her 4 scarves, 3 pairs of gloves, and 2 hats. The colors are in the table. On Monday, she randomly picks out a scarf, hat, and a pair of gloves. What is the probability of Tamara choosing a pair of brown gloves and a red hat?
Tamara has 4 different scarves, 3 pairs of gloves, and 2 hats. The total number of possible outcomes, or ways in which Tamara can choose an item from each category, is given by:
Total number of outcomes = 4 x 3 x 2 = 24
Now, we need to find the number of outcomes in which Tamara chooses a pair of brown gloves and a red hat.
There is only 1 pair of brown gloves and 1 red hat, so there is only 1 way that Tamara can choose these items.
The number of ways in which Tamara can choose a pair of brown gloves and a red hat is 1.
Therefore, the probability of Tamara choosing a pair of brown gloves and a red hat is:
P(choosing a pair of brown gloves and a red hat) = Number of ways to choose brown gloves and red hat / Total number of possible outcomes = 1/24
So, the probability is 1/24.
Tamara likes to mix and match her 4 scarves, 3 pairs of gloves, and 2 hats. The colors are in the table. On Monday, she randomly picks out a scarf, hat, and a pair of gloves. What is the probability of Tamara choosing a pair of brown gloves and a red hat?
A three column table is shown. The first column is titled 'Scarf' and contains 'Red,' 'White,' 'Brown,' and 'Black.' The second column is titled 'Gloves' and contains 'Black,' 'Brown,' and 'Red.' The third column is titled 'Hat' and contains 'White' and 'Red.'
A. one-fourth
B. one-eighth
C. one-tenth
D. start fraction 1 over 6 end fraction
Tamara has 4 scarves, 3 pairs of gloves, and 2 hats. The total number of ways in which Tamara can pick one item from each category is 4 x 3 x 2 = 24 ways.
To find the probability of Tamara choosing a pair of brown gloves and a red hat, we need to determine how many ways she can pick these particular items. There is only one pair of brown gloves and one red hat, therefore, these items can only be selected in one way.
So, the probability of Tamara choosing a pair of brown gloves and a red hat is 1/24.
Therefore, the correct answer is B. one-eighth.
Which events are not independent?
A. You draw two colored marbles without replacement and get one red and one blue.
B. You pull a green tile from a bag of tiles, return it, and then pull a yellow tile.
C. You toss two coins and get one head, one tail.
D. You choose two different ice cream flavors for a cone.
B is the event that is not independent.
If you pull a green tile from a bag of tiles and return it back, the probability of pulling a yellow tile in the second draw is not affected by the outcome of the first draw and remains the same. So, these events are independent.
In A, the events of getting a red marble and a blue marble without replacement are dependent. The probability of getting a blue marble on the second draw depends on the outcome of the first draw.
In C, getting one head and one tail in two coin tosses are independent events. The outcome of the first toss doesn't affect the outcome of the second toss.
In D, choosing two different ice cream flavors for a cone are independent events. The flavor chosen first does not affect the probability of choosing a particular flavor for the second scoop, assuming all flavors are still available.
If a coin is tossed and a number cube is rolled, what is the probability that the coin shows heads and the number cube shows 3?
A. one-half
B. one-ninth
C. start fraction 1 over 6 end fraction
D. start fraction 1 over 12 end fraction
Assuming that the coin and the number cube are fair, the probability of getting heads on the coin is 1/2, and the probability of getting 3 on the number cube is 1/6.
Since the events are independent, the probability of getting both heads and 3 is the product of their individual probabilities:
P(heads and 3) = P(heads) x P(3) = (1/2) x (1/6) = 1/12
So, the probability that the coin shows heads and the number cube shows 3 is 1/12.
Therefore, the correct answer is D. start fraction 1 over 12 end fraction.
On Friday nights the local diner serves three main entrées, each with a choice of vegetable. The entrées are beef, chicken, and fish. The vegetables are spinach, broccoli, and carrots. How many possible dinners (entrée and vegetable combinations) does the diner serve? List them.
There are 3 main entrées and 3 choices of vegetable. To count the total number of dinner combinations, we can use the multiplication principle and multiply the number of choices for each category.
Number of entrées = 3
Number of vegetable choices for each entrée = 3
Therefore, the total number of dinner combinations is:
3 x 3 = 9
Here are the possible dinners, listed by entrée and vegetable:
1. Beef and spinach
2. Beef and broccoli
3. Beef and carrots
4. Chicken and spinach
5. Chicken and broccoli
6. Chicken and carrots
7. Fish and spinach
8. Fish and broccoli
9. Fish and carrots
Therefore, there are 9 possible dinners that the diner serves.
Question 10 of 15
The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.
A circle is divided equally into three sections.
If the spinner is divided into three equal parts, there are three possible outcomes: a consonant, a vowel, or a different consonant.
Using a tree diagram, we can represent the possible outcomes of spinning the spinner twice:
```
C V DC
/ \ / \ / \
C V C V C V
/ \ / \ / \ / \ / \ / \
C V C DC V C V DC DC C DC V
```
where C represents a consonant, V represents a vowel, and DC means a different consonant.
There are three possible outcomes for each spin, so there are 3 x 3 = 9 possible outcomes when the spinner is spun twice.
To land on a consonant both times, we need to choose C in either of the two spins. Therefore, the probability of landing on a consonant both times can be calculated by multiplying the probability of landing on a consonant in the first spin with the probability of landing on a consonant in the second spin, given that a consonant was landed on the first spin.
P(landing on a consonant both times) = P(landing on a consonant in the first spin) x P(landing on a consonant in the second spin | landing on a consonant in the first spin)
P(C1) = 2/3 (Probability of landing on a consonant in the first spin)
P(C2 | C1) = 1/3 (Probability of landing on a consonant in the second spin, given that a consonant was landed on the first spin)
P(landing on a consonant both times) = (2/3) * (1/3) = 2/9
So, the probability of the spinner landing on a consonant both times is 2/9.
What are the rest of the answers?for the rest i really need help
2/9 Is the answer. You're welcome I'll be back with the whole test later.
Its 2023 whats the answer guys its been 20 years
Also AT the time you posted this question it was my B-Day
The answer is 5/9
Your question says that the spinner is divided into four equal parts.
Then you say "My spinner has 3 parts"
So which is it ?
lol Times up! its 2019 now! anywhere..here's MY answers
C
A
B
B
A
B
C
A
A
A
C
D
A
A
Please Sub to my channel on YouTube if this helps!