how many moles of oxygen atoms does 1.2x10^25 diphosphorus pentoxide molecules have?
hwo many oxygen atoms are in 1.25 mol sulphur trioxide?
i don't understand these
thanks
why is it 5 oxygen atoms over 1mol P2O5?
so the second one is
# O atoms = 1.25 mol SO3 x 1molSO3/6.02x10^23 molecules x 3molO/1molSO3 x 6.02x10^23atoms/1molO= 3.75 atomsm O?
When I said the second one was worked the same way I meant the concept was the same but the algebra a different. Let's recapitulate the first one so you can see how the units cancel, then we will do the second one your way and see the units don't cancel so we know it isn't correct.
# mols O atoms in 1.25 x 10^25 P2O5 molecules = 1.25 x 10^25 moleculesP2O5 x (1 mol P2O5/6.02 x 10^23 molecules P2O5) x (5 mols O atoms/1 mol P2O5) = about 104 mols O atoms.
Note that the first term cancels molecules P2O5 in the numerator of 1.25 x 10^25 molecules P2O5 with the denominator of the first term--which converts to mols P2O5). Then the second term has 5 mols O atoms/1 mol P2O5 so the denominator of that term cancels 1 mol P2O5 with the numerator of the second term leaving mols O atoms which is what you want for the answer. I'm sure you must have looked at this way of doing most chemistry problems when you studied dimensional analysis. Now for the second term. You had
O atoms = 1.25 mol SO3 x 1molSO3/6.02x10^23 molecules x 3molO/1molSO3 x 6.02x10^23atoms/1molO= 3.75 atomsm O?
Write this out so you can see it. mol SO3 in numerator of term 2 cancels with denominator of term 3. 6.02 x 10^23 molecules in term 2 denominator cancels with numerator of term 4. Mols O in denominator of term 4 cancels with mols O of numerator of term 3. So you are left with mols SO3 x 3 = 3.75 mols O BUT that isn't the question. The question is for the NUMBER of oxygen atoms (not mols) in 1.25 mols SO3. Here is what you do.
1.25 mols SO3 x (6.02 x 10^23 molecules SO3/1 mol SO3) x (3 atoms O/1 molecule SO3) = ?? molecules O atoms. Note that mols SO3 cancels with mols SO3 and molecules SO3 cancels with molecules SO3 to leave in the numerator atoms Oxygen.
Ah, moles and atoms, huh? Well, don't worry, I'll try to make it a bit more fun for you!
For the first question, if you have a bunch of diphosphorus pentoxide molecules, you want to know how many moles of oxygen atoms you've got floating around. So let's do some math!
Diphosphorus pentoxide has the formula P2O5. And if you remember from chemistry class, there are 5 oxygen atoms in one molecule of P2O5.
Now, you've got 1.2x10^25 molecules of P2O5. So to find the number of moles of oxygen atoms, you just need to multiply that by 5, since you have 5 oxygen atoms per molecule.
So, 1.2x10^25 molecules of P2O5 * 5 oxygen atoms/molecule = your answer! Go, math!
Now onto the second question! We have 1.25 moles of sulfur trioxide and we want to find out how many oxygen atoms are present in that amount.
Sulfur trioxide, also known as SO3, has 3 oxygen atoms in one molecule. So we simply multiply the number of moles by the number of oxygen atoms per molecule to get the answer.
1.25 moles SO3 * 3 oxygen atoms/mole = your answer!
Hope that helps, and remember, atoms can be confusing, but don't be too hard helium yourself!
To answer these questions, we need to use Avogadro's number, which is approximately 6.022 x 10^23. Avogadro's number represents the number of particles (atoms, molecules, ions) in one mole of a substance.
Let's solve these questions step by step.
Question 1: How many moles of oxygen atoms does 1.2x10^25 diphosphorus pentoxide molecules have?
First, we need to know the chemical formula for diphosphorus pentoxide, which is P2O5. From the formula, we can see that there are 5 oxygen atoms in one molecule of diphosphorus pentoxide.
To find the number of moles of oxygen atoms, we can use the following steps:
Step 1: Calculate the number of moles of diphosphorus pentoxide molecules:
Number of moles = Number of molecules / Avogadro's number
Number of moles = 1.2x10^25 / 6.022x10^23 = 19.92
Step 2: Multiply the number of moles of diphosphorus pentoxide by the number of oxygen atoms in one molecule:
Number of moles of oxygen atoms = Number of moles of diphosphorus pentoxide x number of oxygen atoms per molecule
Number of moles of oxygen atoms = 19.92 x 5 = 99.6 moles
Therefore, 1.2x10^25 diphosphorus pentoxide molecules have 99.6 moles of oxygen atoms.
Question 2: How many oxygen atoms are in 1.25 mol sulfur trioxide?
First, we need to know the chemical formula for sulfur trioxide, which is SO3. From the formula, we can see that there are 3 oxygen atoms in one molecule of sulfur trioxide.
To find the number of oxygen atoms, we can use the following steps:
Step 1: Calculate the number of molecules of sulfur trioxide:
Number of molecules = Number of moles x Avogadro's number
Number of molecules = 1.25 x 6.022x10^23 = 7.52875x10^23
Step 2: Multiply the number of molecules of sulfur trioxide by the number of oxygen atoms in one molecule:
Number of oxygen atoms = Number of molecules x number of oxygen atoms per molecule
Number of oxygen atoms = 7.52875x10^23 x 3 = 2.25863x10^24
Therefore, there are approximately 2.25863x10^24 oxygen atoms in 1.25 moles of sulfur trioxide.
I hope this explanation helps you understand how to solve these types of problems.
The 1.25 x 10^25/6.02 x 10^23 converts molecules P2O5 to mols P2O5. I obtained 20.76 but check that.
To find mols oxygen in P2O5, you see there are 5 oxygen atoms per 1 mol P2O5, therefore, there must be 5 x 20.76 mols of oxygen in 20.76 mols P2O5.
One mole of anything contains 6.02 x 10^23 molecules. So there are how many moles P2O5 in 1.2 x 10^25 molecules? There are
1.2 x 10^25 molecules x (1 mol/6.02 x 10^23 molecules) = y moles P2O5.
Then moles oxygen atoms is;
mols oxygen atoms = y moles P2O5 x (5 oxygen atoms/1 mol P2O5) = ??
O in SO3 is done the same way.