A non stop bus goes from one station to another station with a speed of 54 km per hour. The same bus returns from the second station to the first station with a speed of 36 km per hour . Find the average speed of the bus for the entire journey by solved example
THe answer of thIs question is not correct . The correct answer is 43.2 kmph
acc. to me I feel
let the distance be x km
time for first bus = x/54
time for 2nd bus = x/36
total time = x/54 + x/36 = 90x/1944
total distance = 2x
average speed = total distance / total time
= 2x / (90x/1944) km/h
= 2x*1944/90x km/hr
= 43.2km/hr
let distance between the station be x km while going speed=54km/hr so time taken =x/54hr while returning speed=36km/hr
so time taken=x/36
Total time=x/54+x/36
(2x+3x)/108
average speed=total distance/total time
=(x+x)5x/108
=2x 108/5x
=216/5
=43.2km/h
Solution
w.k.t distance between the station be x km while going speed=54km/hr
time taken = x/54hr while returning speed=36km/hr
time taken=x/36
Total time=x/54+x/36
(2x+3x)/108
[Average speed=Total distance/Total time]
=(x+x)5x/108
=2x 108/5x
=216/5
=43.2km/h
Let the distance between the two station be x
While going speed = 54 km/hr
So,
Time taken = x/54
While returning speed = 36 km/hr
So,
Time taken = x/36
Total time = x/54 + x/36
= 5x/108
Average speed = total distance /
total time = x+x/5x/108
= 2x/5x/108
= 2x ×108/5x
= 43.2 km/hr
Answer is 43.2km/hrs
Let the distance between the two station be x
While going speed = 54 km/hr
So,
Time taken = x/54
While returning speed = 36 km/hr
So,
Time taken = x/36
Total time = x/54 + x/36
= 5x/108
Average speed = total distance /
total time = x+x/5x/108
= 2x/5x/108
= 2x ×108/5x
= 43.2 km/hr
Let the distance between the two station be x
While going speed = 54 km/hr
So,
Time taken = x/54
While returning speed = 36 km/hr
So,
Time taken = x/36
Total time = x/54 + x/36
= 5x/108
Average speed = total distance /
total time = x+x/5x/108
= 2x/5x/108
= 2x ×108/5x
= 43.2 km/hr
Distance=x
Answer = 43.2 km h-¹
I don't understand
Let the distance between the two stations be x
While going speed = 54 km/hr
So,
Time taken = x/54
While returning speed = 36 km/hr
So,
Time taken = x/36
Total time = x/54 + x/36
= 5x/108
Average speed = total distance /
total time = x+x/5x/108
= 2x/5x/108
= 2x ×108/5x
= 43.2 km/hr
I see that there has been some confusion regarding the solution of this problem. Here is the correct solution:
Let the distance between the two stations be x km.
While going from the first station to the second station, the speed of the bus is 54 km/hr. Therefore, the time taken for this part of the journey is:
time = distance / speed = x / 54
While returning from the second station to the first station, the speed of the bus is 36 km/hr. Therefore, the time taken for this part of the journey is:
time = distance / speed = x / 36
The total time taken for the entire journey can be found by adding the two times:
total time = x/54 + x/36 = 5x/108
The total distance covered is 2x km (since the bus travels the same distance twice).
Therefore, the average speed of the bus for the entire journey is:
average speed = total distance / total time = (2x km) / (5x/108 hr)
= (2x km) * (108/5x hr)
= 43.2 km/hr
Therefore, the average speed of the bus for the entire journey is 43.2 km/hr.
Love
let the distance be x km
time for first bus = x/54
time for 2nd bus = x/36
total time = x/54 + x/36 = 5x/108
total distance = 2x
avg speed = total distance / total time
= 2x / (5x/108) km/h
= 108/5 km/h
= 21.6 km/h