Calculate the mass f CaCo3, in Kg, needed to slurry to extract the SO2 present in 10m3 of industrial waste gases at rtp, if SO2 comprises 10% of this volume.
10 m^3 = 10,000 L.
10% x 10,000 = 1000 L SO2
CaCO3 + SO2 ==> CaSO3 + CO2
Calculate n = mols SO2 in 1000 L.
PV = nRT
P = 1 atm
V = 1000 L
R = 0.08205
T = 298 K
Solve for n = number of mols SO2.
Convert that to mols CaCO3. mols CaCO3 - mols SO2 (look at the coefficients in the blaanced equation.).
Then grams CaCO3 = mols CaCO3 x molar mass CaCO3. Convert to kg. Post your work if you get stuck.
okay thank you :)
PV/RT = n
(1 x 1000)/(0.08205 x 298) = n
1000/24.45 = 40 moles in SO2 in 1000L
grams of CaCO3 = moles of CaCO3 X molar mass CaCO3
gram = 40g x 100g/mol
gram = 4000g
Convert to kg = 4kg
To calculate the mass of CaCO3 needed to slurry to extract SO2, we need to follow a few steps:
Step 1: Calculate the volume of SO2 in the waste gases.
Given that SO2 comprises 10% of the volume, we can calculate the volume of SO2:
Volume of SO2 = (10% * 10m3) = 1m3
Step 2: Convert the volume of SO2 to mass.
To do this, we need to know the density of SO2 at standard temperature and pressure (STP). The density of SO2 at STP is approximately 2.926 kg/m3. Therefore, we can calculate the mass of SO2:
Mass of SO2 = Volume of SO2 * Density of SO2
Mass of SO2 = 1m3 * 2.926 kg/m3 = 2.926 kg
Step 3: Determine the stoichiometric ratio between CaCO3 and SO2.
The balanced chemical equation for the reaction between CaCO3 and SO2 is:
CaCO3 + SO2 -> CaSO3 + CO2
From the equation, we can see that one mole of CaCO3 reacts with one mole of SO2.
Step 4: Convert the mass of SO2 to moles.
To do this, we need to know the molar mass of SO2, which is approximately 64.06 g/mol. Therefore, we can calculate the moles of SO2:
Moles of SO2 = Mass of SO2 / Molar mass of SO2
Moles of SO2 = 2.926 kg * 1000 g/kg / 64.06 g/mol = 45.7 mol
Step 5: Convert the moles of SO2 to moles of CaCO3.
Since the stoichiometric ratio is 1:1, the moles of CaCO3 will also be 45.7 mol.
Step 6: Convert the moles of CaCO3 to mass.
To do this, we need to know the molar mass of CaCO3, which is approximately 100.09 g/mol. Therefore, we can calculate the mass of CaCO3:
Mass of CaCO3 = Moles of CaCO3 * Molar mass of CaCO3
Mass of CaCO3 = 45.7 mol * 100.09 g/mol = 4573.7 g = 4.5737 kg
Therefore, the mass of CaCO3 needed to slurry to extract the SO2 present in 10m3 of industrial waste gases at RTP, where SO2 comprises 10% of this volume, is approximately 4.5737 kg.