Specify the concentration of each ion in solution for the following:
.10 M AlCl3 (aq) and .15 M (NH4)2SO4 (aq)
AlCl3 ==> Al^3+ + 3Cl^-
So 1 mol AlCl3 contains 1 mol Al^3+ ions and 3 mols Cl^-. Does that tell you that 0.1M AlCl3 contains 0.1 mol Al^3+ and 0.3M Cl^-?
Yes
I made a typo. That last sentence should read as follows:
Does that tell you that 0.1M AlCl3 contains 0.1 M Al^3+ and 0.3M Cl^-?
To determine the concentration of each ion in a solution, we need to consider the dissociation of the given compounds.
1. AlCl3 (aq)
AlCl3 dissociates into Al3+ ions and Cl- ions.
The concentration of Al3+ ions in solution will be the same as the concentration of AlCl3, which is 0.10 M.
The concentration of Cl- ions in solution will also be 0.10 M since AlCl3 dissociates into one Al3+ ion and three Cl- ions.
Therefore, the concentration of each ion in the solution of 0.10 M AlCl3 (aq) is:
Al3+ ions: 0.10 M
Cl- ions: 0.10 M
2. (NH4)2SO4 (aq)
(NH4)2SO4 dissociates into 2 NH4+ ions and 1 SO4^2- ion.
The concentration of NH4+ ions in solution will be twice the concentration of (NH4)2SO4, which is 0.15 M. Thus, the concentration of NH4+ ions is 2 × 0.15 M = 0.30 M.
The concentration of SO4^2- ions in the solution will be the same as the concentration of (NH4)2SO4, which is 0.15 M.
Therefore, the concentration of each ion in the solution of 0.15 M (NH4)2SO4 (aq) is:
NH4+ ions: 0.30 M
SO4^2- ions: 0.15 M