Shantanu's age is 3 years more than Tanya's age.The sum of their ages is 27 years.Find their ages.
Let's start by assigning variables to the ages of Shantanu and Tanya.
Let S represent Shantanu's age
Let T represent Tanya's age
According to the information given:
Shantanu's age is 3 years more than Tanya's age.
This can be written as:
S = T + 3
The sum of their ages is 27 years.
This can be written as:
S + T = 27
Now we have a system of two equations:
Equation 1: S = T + 3
Equation 2: S + T = 27
To solve this system, we can substitute Equation 1 into Equation 2:
(T + 3) + T = 27
Simplifying the equation, we get:
2T + 3 = 27
Subtracting 3 from both sides, we have:
2T = 24
Dividing both sides by 2, we get:
T = 12
Now we can substitute the value of T back into Equation 1 to find S:
S = 12 + 3
S = 15
Therefore, Shantanu is 15 years old and Tanya is 12 years old.
To find Shantanu and Tanya's ages, we can set up a system of equations based on the given information.
Let's assume Tanya's age as 'x' years.
According to the given information, Shantanu's age is 3 years more than Tanya's age. So, Shantanu's age can be represented as 'x + 3' years.
The sum of their ages is 27 years, which gives us the equation:
x + (x + 3) = 27
Simplifying the equation:
2x + 3 = 27
Now, we can solve the equation to find the value of 'x'.
Subtracting 3 from both sides:
2x = 24
Dividing both sides by 2:
x = 12
So, Tanya's age is 12 years.
Now we can substitute the value of 'x' back into the equation to find Shantanu's age:
Shantanu's age = x + 3 = 12 + 3 = 15
Therefore, Tanya's age is 12 years and Shantanu's age is 15 years.
t + t + 3 = 27
2t = 24
Tanya = 12
Let Tanya's age be x
Shantanu's age = x+3
A/q
X + x + 3 = 27
X+x = 27-3
X+x= 24
x^2 = 24
X^2= 24 prime factorization by 2
X^2=12^2
Cancel both the exponent
So Tanya's age is 12 nd shantanu's age is 12 +3=15