An object is projected at an angle of elevation of 45 degree with a velocity of 100m/s. Calculate it's range
Range = Vo^2*sin(2A)/g.
Anybody answer please
An object is projected of elevation of 45 degree with a velocity of velocity of 100 m/s. Calculate its Range
To calculate the range of a projectile launched at an angle of elevation, you can use the following equation:
Range (R) = (V^2 * sin(2θ)) / g
Where:
- V is the initial velocity of the projectile
- θ is the angle of elevation
- g is the acceleration due to gravity (approximately 9.8 m/s²)
In this case, the initial velocity (V) is 100 m/s and the angle of elevation (θ) is 45 degrees.
First, let's convert the angle from degrees to radians:
θ (in radians) = θ (in degrees) * π / 180
θ (in radians) = 45 * π / 180
θ (in radians) = π / 4
Now, we can substitute the values into the equation to calculate the range:
R = (100^2 * sin(2 * π / 4)) / 9.8
Simplifying further:
R = (100^2 * sin(π / 2)) / 9.8
R = (100^2 * 1) / 9.8
R = 10000 / 9.8
R ≈ 1020.41 m
Therefore, the range of the projectile is approximately 1020.41 meters.