a man gives 40% of his money to his children and 20% of the remaining to a trust. if he is still left with rs.9600.what did he originally have?

Let's assume the man initially had X amount of money.

From the given information, we know that the man gives 40% of his money to his children. This means that he has (100% - 40%) = 60% of his money remaining.

Therefore, the remaining amount after giving money to his children is 60% of X, which is 0.6X.

Next, we are told that he gives 20% of the remaining amount to a trust. This means he has (100% - 20%) = 80% of the remaining amount left.

Therefore, the amount of money he has after giving money to his children and the trust is 80% of 0.6X, which is (0.8 * 0.6X) = 0.48X.

According to the given information, the man is still left with Rs. 9600, which is equal to 0.48X.

So, we can set up the equation: 0.48X = 9600.

To find X, we can solve for X by dividing both sides of the equation by 0.48: X = 9600 / 0.48 = Rs. 20,000.

Therefore, the man originally had Rs. 20,000.