5x-4y=10
2x+8y=4
rewrite #1 and you get
10x-8y=20
2x+8y=4
Now add the two equations and y goes away. Solve for x, then get y.
Thanks Steve.
But how???
Please explain it.
If you add the two equations, you get
12x = 24
because -8y+8y = 0
Now you know x=2, so y=0
To solve this system of equations, you can use either the substitution method or the elimination method. Let's use the elimination method to find the values of x and y.
Step 1: Multiply the first equation by 2 and the second equation by 5 in order to eliminate the x term.
Original equations:
5x - 4y = 10
2x + 8y = 4
Modified equations:
10x - 8y = 20
10x + 40y = 20
Step 2: Now, subtract the two modified equations to eliminate the x term.
(10x - 8y) - (10x + 40y) = 20 - 20
-8y - 40y = 0
-48y = 0
Step 3: Solve for y.
-48y = 0
y = 0
Step 4: Substitute the value of y (y = 0) back into one of the original equations to find the value of x. Let's use the first equation.
5x - 4(0) = 10
5x = 10
x = 2
Therefore, the solution to the system of equations is x = 2 and y = 0.