(3y-6)/3 +4 <= -2
OR
(4y-8)/2 -1 >= 5
Someone please help me and show me how to solve this. The numbers in parentheses are over a fraction, which is the number next to the slash. I can do the graphing myself, I just need help solving it.
John
answered
3y-6 <= -18
3y <= -24
y <= -8
(4y-8)/2 > 6
4y-8 >12
4y > 20
y > 5
with OR
the solution is y is less than or = -8 or y>5
Earth
answered
Earth
answered
John
answered
Earth
answered
y <= -4 or y >=5
y <= 6 or y >= -5
y <= -5 or y >= 5
y <= 4 or y >= -5
Gmoney
answered
Unknown
answeredA
niahcondones
answered
Explain Bot
answered
1. Solve the first inequality and express y in terms of the solution.
2. Solve the second inequality and express y in terms of the solution.
3. Compare the two solutions to determine the overlapping region or solution.
Let's begin with the first inequality:
(3y - 6)/3 + 4 <= -2
1. Start by subtracting 4 from both sides to isolate the fraction:
(3y - 6)/3 <= -6
2. Multiply both sides of the equation by 3 to eliminate the fraction:
3 * (3y - 6)/3 <= -6 * 3
3y - 6 <= -18
3. Add 6 to both sides to isolate the y term:
3y <= -18 + 6
3y <= -12
4. Finally, divide both sides by 3 to solve for y:
y <= -12/3
y <= -4
Now let's move on to the second inequality:
(4y - 8)/2 - 1 >= 5
1. Start by adding 1 to both sides of the equation:
(4y - 8)/2 >= 5 + 1
2. Simplify the right side:
(4y - 8)/2 >= 6
3. Multiply both sides of the equation by 2 to eliminate the fraction:
2 * (4y - 8)/2 >= 6 * 2
4y - 8 >= 12
4. Add 8 to both sides to isolate the y term:
4y >= 12 + 8
4y >= 20
5. Finally, divide both sides by 4 to solve for y:
y >= 20/4
y >= 5
Now we compare the solutions of the two inequalities:
For the first inequality: y <= -4
For the second inequality: y >= 5
Since these two solutions do not overlap, it means there is no shared solution to the given system of inequalities. Therefore, there is no graph to be drawn as there is no common region that satisfies both inequalities.
