The distance D covered by a falling ball varies as the square of the time take T, calculate the distance when the time taken is 13 seconds and the time taken for a distance of 648m.
D = kT^2
when T=13, D = 169k
when D=648, T = √(648/k)
Supply the missing info, and you can get numbers.
as in i need d solution
To start, we need to determine the relationship between distance and time in the given scenario. According to the problem, the distance covered by a falling ball varies as the square of the time taken. So, we have:
D = kT^2
Where D is the distance covered, T is the time taken, and k is a constant.
Now, we can proceed to solve the problem. We are given two scenarios:
1. When the time taken is 13 seconds.
2. When the distance taken is 648 meters.
Let's calculate the value of k using the second scenario:
648 = k(13^2)
648 = k(169)
k = 648/169
k ≈ 3.835
Now that we have the value of k, we can use it to calculate the distance in the first scenario (when the time taken is 13 seconds):
D = 3.835(13^2)
D = 3.835(169)
D ≈ 648.4 meters
Therefore, when the time taken is 13 seconds, the distance covered by the falling ball is approximately 648.4 meters.