The function,p(d)=1+d/33, gives the pressure in atmospheres(atm), at a depth d in the sea (d is in feet).Note that p(0)=1 atm, p(33)=2, and so on. Find the pressure at 120 feet.
To find the pressure at 120 feet, you can substitute 120 for d in the given function, p(d) = 1 + d/33.
p(120) = 1 + 120/33
= 1 + 3.6363636...
Now, let's simplify the decimal value to three decimal places:
p(120) ≈ 1 + 3.636
≈ 4.636
Therefore, the pressure at 120 feet in the sea is approximately 4.636 atmospheres (atm).
To find the pressure at 120 feet, we can substitute the value of d = 120 into the function p(d) = 1 + d/33.
So, p(120) = 1 + 120/33.
To simplify, we need to perform the division first:
120 / 33 = 3.6363 (rounded to four decimal places).
Now, we can substitute this value back into the equation:
p(120) = 1 + 3.6363.
Adding the values:
p(120) = 4.6363.
Therefore, the pressure at 120 feet is approximately 4.6363 atmospheres (atm).