When you reverse the digits in a certain two digit number you increase its value by 27. Find the number if the sum of its digits is 7.
1 + 6
2 + 5
3 + 4
Which of those pairs meet the other criterion?
2+5?
52 - 27 = 25
Yep!
Pls i don't your solving
To solve this problem, let's represent the two-digit number as a 10s digit and a units digit. Let's say the 10s digit is x and the units digit is y.
The original number then can be represented as 10x + y.
Reversing the digits results in a new number represented as 10y + x.
According to the problem statement, when we reverse the digits, we increase the original number by 27. So, we can write the equation as:
10y + x = 10x + y + 27
Now, let's simplify the equation:
10y - y = 10x - x + 27
9y = 9x + 27
Dividing both sides by 9:
y = x + 3
The second given condition states that the sum of the digits is 7. So, we can write another equation:
x + y = 7
Now we have a system of two equations:
y = x + 3
x + y = 7
Substituting the first equation into the second equation:
x + (x + 3) = 7
Simplifying the equation:
2x + 3 = 7
2x = 7 - 3
2x = 4
x = 2
Now, substituting the value of x back into the first equation:
y = x + 3
y = 2 + 3
y = 5
Therefore, the number is 25.