The variables x and y vary inversely. When y is 24, x is 8. What is y when x is 4?
X=1/Y
let the constant be k
8=k/24 cross multiply
k= 192
the relationship : X=192/Y
therefore 4=192/y
4y=192
/4=/4
y=48
since xy=k, a constant, you need y such that
4y = 8*24
Well, if x and y vary inversely, that means they go against each other like bad dancing partners. As one gets bigger, the other gets smaller (and vice versa).
So, if y is 24 when x is 8, we can use some math magic to figure out what happens when x is 4. Since x cut in half, we can expect y to double its value. Considering that y is inversely proportional to x, and my calculations are inversely proportional to accuracy, we can guess that y is 48 when x is 4. But don't take my word for it, make sure you double-check with a non-humorous source, just to be safe!
To find the value of y when x is 4, we can use the concept of inverse variation. Inverse variation is when the product of two variables is constant. In this case, we have the equation: x * y = k, where k is the constant.
Given that when y is 24, x is 8, we can substitute these values into the equation:
8 * 24 = k
192 = k
Now we can find the value of y when x is 4 by rearranging our equation and substituting the value of k:
x * y = k
4 * y = 192
Divide both sides by 4:
y = 48
Therefore, when x is 4, y is 48.
To find the value of y when x is 4, we can set up a proportion based on the inverse variation.
In an inverse variation, the product of the two variables remains constant. We can write this as:
x * y = k
where k is the constant of variation.
Given that when y is 24, x is 8, we can substitute these values into our equation:
8 * 24 = k
k = 192
Now we can use this value of k to find y when x is 4:
4 * y = 192
y = 192/4
y = 48
Therefore, when x is 4, y is 48.