find heat 45 g at 43c to 23 caculate sph
To calculate the specific heat (sph), we need to know the amount of heat (Q), the mass (m), and the change in temperature (ΔT).
Given:
Mass (m) = 45 g
Initial temperature (T1) = 43°C
Final temperature (T2) = 23°C
Step 1: Calculate the heat (Q) absorbed or released using the formula:
Q = m * sph * ΔT
ΔT = T2 - T1
ΔT = 23°C - 43°C
ΔT = -20°C
Substituting the values:
Q = 45 g * sph * (-20°C)
Step 2: Rearrange the equation to find the specific heat (sph):
sph = Q / (m * ΔT)
sph = (45 g * sph * (-20°C)) / (45 g * (-20°C))
Step 3: Simplify and solve for sph:
Dividing both sides of the equation by 45 g * (-20°C):
1 = sph / (45 g * (-20°C))
Now, divide both sides by -20°C to isolate sph:
sph = 1 / (45 g * (-20°C))
sph = -1 / (900 g°C)
The specific heat (sph) of the given substance is approximately -0.0011 g/°C. Note that the negative sign indicates that the substance released heat rather than absorbed it.