a person falls flat on their back on some slipper ice and is unconscious for a second. the horizontal position of their legs, torso and head from their feet is given by 0.48m, 1.35m and 1.7m respectively and their weights are 30kg, 50kg and 10kg. they try to sit up on the ice which is so slippery that they are not able to move their horizontal centre of mass. the new positions of their legs, torso and head from their feet are 0.16m, 0.52m, and 0.72m. what is the change in position of the person's feet?
To determine the change in position of the person's feet, we need to find the horizontal displacement for each segment of the body (legs, torso, and head) and then sum them up.
Step 1: Calculate the initial horizontal positions of the body segments from the feet. These measurements are given in the problem:
Legs: 0.48 m
Torso: 1.35 m
Head: 1.7 m
Step 2: Calculate the final horizontal positions of the body segments from the feet. These measurements are given in the problem after the person sits up:
Legs: 0.16 m
Torso: 0.52 m
Head: 0.72 m
Step 3: Calculate the horizontal displacement for each body segment by subtracting the final position from the initial position:
Legs: 0.16 m - 0.48 m = -0.32 m
Torso: 0.52 m - 1.35 m = -0.83 m
Head: 0.72 m - 1.7 m = -0.98 m
Step 4: Sum up the horizontal displacements of all body segments to find the change in position of the person's feet:
-0.32 m + -0.83 m + -0.98 m = -2.13 m
Therefore, the change in position of the person's feet is -2.13 meters. The negative sign indicates that the feet have moved to the left or backwards relative to the initial position.