The sum of the angle measures of a polygon w/ "s" sides is 2880. Find "s"
Please help with step-by-step explanation, so I can fully understand it. Thank you.
would it be this:
(n-2)180=2880
then
180n-360=2880
then
180n=3240
then
n=18
http://www.mathsisfun.com/geometry/interior-angles-polygons.html
Yes, that's correct
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Multiply ( 1*34) +(14* 56)
To find the number of sides (s) of a polygon when the sum of its angle measures is given, you can use the following formula:
sum of angle measures = (s - 2) * 180
In this case, you are given that the sum of the angle measures is 2880. Therefore, you can set up the equation as follows:
2880 = (s - 2) * 180
Now, let's solve for s.
Divide both sides of the equation by 180:
2880 / 180 = (s - 2)
Simplify:
16 = s - 2
To isolate s, add 2 to both sides of the equation:
16 + 2 = s
Therefore, s = 18.
So, the polygon has 18 sides.