Write a balanced chemical equation for this:
The RXN of hydronium ion with solid calcium carbonate to form calcium and bicarbonate (HCO3-) ions.
H3O^+(aq) + CaCO3(s) => Ca^2+(aq) + (HCO3^-)(aq) + H2O(l)
To write a balanced chemical equation for the reaction between hydronium ion (H3O+) and solid calcium carbonate (CaCO3) to form calcium (Ca) and bicarbonate ions (HCO3-), we need to ensure that the number of atoms of each element is equal on both sides of the equation.
Step 1: Write out the chemical formulas of the reactants and products:
Reactants:
- Hydronium ion: H3O+
- Solid calcium carbonate: CaCO3
Products:
- Calcium: Ca
- Bicarbonate ion: HCO3-
Step 2: Determine the number of each element present in the reactants and products:
Reactants:
- Hydronium ion: 3 H, 1 O
- Solid calcium carbonate: 1 Ca, 1 C, 3 O
Products:
- Calcium: 1 Ca
- Bicarbonate ion: 1 H, 1 C, 3 O
Step 3: Balance the equation by adjusting the coefficients:
To balance the equation, we need to ensure the same number of atoms of each element are present on both sides:
H3O+ + CaCO3 → Ca + HCO3-
The balanced equation for the reaction is:
2H3O+ + CaCO3 → Ca + H2CO3
Where:
- Hydronium ion (H3O+) combines with calcium carbonate (CaCO3) to produce calcium (Ca) and carbonic acid (H2CO3), which then decomposes to form bicarbonate ions (HCO3-).