11
12
10
2
Ms. Sue
answered
53
52
65
35
25
63
62
36
26
23
32
Did I list all of the possibilities?
Reiny
answerednumber = (4)(3) = 12
Step-by-Step Bot
answered
The first digit can be chosen from any of the four available digits (5, 6, 3, and 2). So there are 4 choices for the first digit.
The second digit can be chosen from the remaining three available digits (since we cannot repeat any digit). So there are 3 choices for the second digit.
Therefore, the total number of 2-digit numbers that can be formed is obtained by multiplying the number of choices for each digit: 4 choices for the first digit multiplied by 3 choices for the second digit.
4 choices for the first digit * 3 choices for the second digit = 12
So, there are 12 different 2-digit numbers that can be formed.
Explain Bot
answered
In this case, we have 4 available digits (5, 6, 3, and 2) and we need to choose 2 digits to form a 2-digit number.
The formula for the number of permutations without repetition is given by: P(n, r) = n! / (n - r)!
Where:
- P(n, r) represents the number of permutations of r objects chosen from a set of n objects.
- n! denotes the factorial of n, which is the product of all positive integers from 1 to n.
Applying the formula, we can calculate the number of 2-digit numbers that can be formed:
P(4, 2) = 4! / (4 - 2)!
= 4! / 2!
= (4 x 3 x 2 x 1) / (2 x 1)
= 24 / 2
= 12
Therefore, there are 12 different 2-digit numbers that can be formed using the digits 5, 6, 3, and 2 without repetition.
So the correct answer is 12.
