. In the following reaction: Fe2O3 + 3C → 2Fe + 3CO; how many grams of C are needed to react with 16.5 g Fe2O3?
To determine the grams of C needed to react with 16.5 g of Fe2O3, we need to use stoichiometry and molar masses.
1. Start by calculating the molar masses of Fe2O3 and C:
- Molar mass of Fe2O3 = (2 * molar mass of Fe) + (3 * molar mass of O)
- Molar mass of Fe = atomic mass of Fe
- Molar mass of C = atomic mass of C
2. Use the molar mass of Fe2O3 to convert grams of Fe2O3 to moles:
- Moles of Fe2O3 = (grams of Fe2O3) / (molar mass of Fe2O3)
3. Apply the stoichiometry of the balanced equation to determine the moles of C required:
- Moles of C = (moles of Fe2O3) * (moles of C / moles of Fe2O3)
4. Convert moles of C to grams:
- Grams of C = (moles of C) * (molar mass of C)
Now, let's calculate it step by step:
1. Molar mass:
- Molar mass of Fe2O3 = (2 * 55.845 g/mol Fe) + (3 * 16.00 g/mol O) = 159.69 g/mol
- Molar mass of C = 12.01 g/mol
2. Moles of Fe2O3:
- Moles of Fe2O3 = 16.5 g Fe2O3 / 159.69 g/mol = 0.103 moles
3. Moles of C:
- Moles of C = 0.103 moles Fe2O3 * (3 moles C / 1 mole Fe2O3) = 0.309 moles
4. Grams of C:
- Grams of C = 0.309 moles C * 12.01 g/mol = 3.71 grams
Therefore, 3.71 grams of C are needed to react with 16.5 grams of Fe2O3.
To determine the number of grams of C needed to react with 16.5 g of Fe2O3, we need to use the stoichiometry of the balanced chemical equation.
Step 1: Calculate the molar masses:
- Molar mass of Fe2O3 (iron(III) oxide) = 2 * atomic mass of Fe + 3 * atomic mass of O = 2 * 55.85 g/mol + 3 * 16.00 g/mol = 159.69 g/mol
- Molar mass of C (carbon) = 12.01 g/mol
Step 2: Determine the moles of Fe2O3:
Using the formula: moles = mass / molar mass
moles of Fe2O3 = 16.5 g / 159.69 g/mol
Step 3: Determine the moles of C using the stoichiometry of the balanced equation:
According to the balanced equation, the ratio of moles of Fe2O3 to moles of C is 1:3.
moles of C = moles of Fe2O3 * (3 moles of C / 1 mole of Fe2O3)
Step 4: Calculate the grams of C:
Using the formula: mass = moles * molar mass
grams of C = moles of C * molar mass of C
Now we can calculate the grams of C needed to react with 16.5 g of Fe2O3.
Fe2O3 + 3C → 2Fe + 3CO
mols Fe2O3 = grams/molar mass = ?
mols C needed = 3x that. Look at the coefficients.
g C = mols C x atomic mass C = ?