Question

a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the beam weights of mass 10 kg and 8kg are placed near p and q respectively one each end of the beam.calculate the reaction at p and q?

Answer 1

After sketching the diagram.

P+Q=220 N (Newton)
Taking moment about point P
40*2 + 80*5 = 4Q +100*1
80 + 400 = 4Q + 100
480 - 100 = 4Q
380 = 4Q
Q = 380/4
Q = 95 N
P + Q = 220 N
P +95 = 220
P = 220 - 95 = 125 N
P =125 N

Answer 2

p and q are 4.0 m apart

moments around q
4 p = (10 * 5) + (4 * 2) - (8 * 1)
p = 12.5
Rp = 12.5 g

moments around p
4 q = (8 * 5) * (4 * 2) - (10 * 1)
q = 9.5
Rq = 9.5 g

Answer 3

Pls if possible can you snap and post

the diagram for clarity

Answer 4

I want to learn physics very well

Answer 5

Correct

Answer 6

I dont understand the calculation

Answer 7

i doot understand the calculation

Answer 8

clarifying

Rp = 12.5 * g

Rq = 9.5 * g

Answer 9

I don't know that why am asking you

Answer 10

i need more clarity on why it had to be done that way

Answer 11

am not getting the sense

Answer 12

i dont understand the solutions

Answer 13

Correct

Answer 14

How did you get 220N

Answer 15

Tnks

Answer 16

Pls be more specific and do show more workings on this particular question because am also confused

Answer 17

Thank you very much Nkanu.But could you post the diagram

Answer 18

Please I don't understand, can you throw more lights?.

Answer 19

I kind of understood 90 percent of what this person nkanu did but I don't understand that 4Q, how Q is 4Q

Answer 20

Awesome .thanks I understood it all

Answer 21

I understood the solving but pls can u sketch the diagram for better understanding

Answer 22

Thanks so much but pls clarify more onthe diagram

Answer 23

What is *

Answer 24

Pls sketch the diagram

Answer 25

I don't understand the explanation here😔😔

Answer 26

How did u get 220