I am confused with this problem:
By what number does 9.46 exceed 3.928?
Would I subtract the two numbers?
Yes. Subtract.
I understand now. Thanks
:-) You're welcome.
Yes, to find out by what number 9.46 exceeds 3.928, you subtract 3.928 from 9.46.
Here's how you can do it step by step:
1. Write down the larger number (9.46) on top and the smaller number (3.928) underneath it.
9.46
- 3.928
2. Start subtracting the corresponding digits from right to left.
a) Subtract the ones place (8 - 6 = 2) and write down the result underneath.
9.46
- 3.928
----
2
b) Subtract the tenths place (2 - 2 = 0) and write down the result underneath.
9.46
- 3.928
----
20
c) Subtract the hundredths place (4 - 9 = -5). Since we don't have a digit to subtract from 4, we borrow 1 from the tens place.
9.46
- 3.928
----
-5
Now, add 10 to -5 (borrowed 1 from the tens place) to get 5.
9.46
- 3.928
----
5
3. The result is 5. Therefore, 9.46 exceeds 3.928 by 5.
So, by subtracting 3.928 from 9.46, you find that 9.46 exceeds 3.928 by 5.