A baseball player hits a pop fly that goes directly up in the air with an initial velocity of 45 m/s. What is the maximum height the base ball reaches?
Work: initial velocity = 45 m/s, gravity= -9.8 m/s, final velocity = 0 m/s
Vf^2 = Vo^2 + 2g*h.
h = ?
To find the maximum height reached by the baseball player's pop fly, we can use the following formula:
Final velocity^2 = Initial velocity^2 + 2 * acceleration * displacement
Since the final velocity is 0 m/s (the baseball reaches its highest point and then falls back down), we can rearrange the formula to solve for the displacement, which represents the maximum height reached:
Displacement = (Final velocity^2 - Initial velocity^2) / (2 * acceleration)
Plugging in the given values, we have:
Displacement = (0^2 - 45^2) / (2 * (-9.8))
Displacement = (-2025) / (-19.6)
Displacement = 103.3163 meters
Therefore, the maximum height reached by the baseball is approximately 103.32 meters.