I have no idea how to even start this, can someone kinda "point me in the right direction" so to speak.

-Compute the time(t) it will take for a tool to fall to the ground when a worker drops from the top of the building.
-Function:h(t)=-16t^2th0 where t is the time in seconds, h is the height in feet at time t, and h0 is the height of the building
-so if the bulding is 500 feet high, then h0 = 500 and the function would be h(t)=-16t^2 + 500
-when the tool reaches the ground, the height of the tool is zero(0) so the function would be: -16t^2 + 500 = 0
-Solve this quadratic equation for t

Reiny Reiny answered
8 years ago

-16t^2 + 500 = 0

16t^2 = 500
t^2 = 500/16 = 31.25
t = √31.25 = appr 5.59 seconds

Emma Emma answered
8 years ago

If I was graphing this it'll open upwards right?

Damon Damon answered
8 years ago

h(t) = 500 - 16 t^2

opens down (sheds water)
if the ground were not at h=0 the tool would keep falling into negative h. (down a deep hole)
The tool is at its maximum height, h = 500 at the beginning when h = 500 and t = 0

It is also below 500 feet in the imaginary time before t = 0, as if it were thrown up and reached 500 feet at zero speed just as you hit your stopwatch:)

Emma Emma answered
8 years ago

Oh ok, thank you so much!

SuperSuperHappyFace :DD SuperSuperHappyFace :DD answered
10 months ago

Question

What does Psychrometer mean?

Answer Choices
* A tool used to measure air temperature
* A tool used to measure the speed of wind
* A tool used to measure the relative humidity in the atmosphere

Explain Bot Explain Bot answered
7 months ago

To compute the time it will take for the tool to fall to the ground, you will need to solve the quadratic equation -16t^2 + 500 = 0.

To solve this equation for t, you can follow these steps:

Step 1: Start with the quadratic equation: -16t^2 + 500 = 0.

Step 2: Move the constant term (500) to the right side of the equation, changing the sign: -16t^2 = -500.

Step 3: Divide both sides of the equation by the coefficient of t^2 (-16) to isolate the term t^2: t^2 = 500/16.

Step 4: Simplify the right side of the equation: t^2 = 31.25.

Step 5: Take the square root of both sides to solve for t: t = ±√31.25.

Therefore, the time it will take for the tool to fall to the ground is t = ±√31.25.

Note that since time cannot be negative in this context, we discard the negative solution. Thus, the time it will take for the tool to fall to the ground is t = √31.25.

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