2) subtract the two equations to erase the y value (since 2y-2y=0) and solve for x, then add them to erase the x value (since -3x+3x=0) and solve for y. ur x values should be -8.5 and 7.5 respectively. i don't know how to do #1
step by srep the problems
1) x+ y=13
22x + 36y =356
2)-3x +2y=8
3x + 2y=8
#1 use substitution. subsitute y with y=13-X, and solve for x.
22X+36(13-X)=356
-14X=-112
x=8
8+y=13
y=5
To solve the first problem, which is to find the values of x and y in the equations:
1) x + y = 13
2) 22x + 36y = 356
We can solve this using substitution.
1) Start by solving the first equation for one variable in terms of the other. Let's solve for y in terms of x.
y = 13 - x
2) Now substitute this value of y into the second equation.
22x + 36(13 - x) = 356
3) Simplify and solve for x.
22x + 468 - 36x = 356
-14x + 468 = 356
-14x = -112
x = -112 / -14
x = 8
4) Now substitute the value of x back into the first equation to solve for y.
x + y = 13
8 + y = 13
y = 13 - 8
y = 5
So the solution to the first problem is x = 8 and y = 5.