Ok so ive gotten this far on finding the points of (2004, 3370) and (2007, 3552)
can someone help me find out the equation in y=mx+b form please
The slope is m = (3552-3370)/(2007-2004) = 60 2/3 = 182/3
You can use the equation
3370 = (182/3)(2004)+ b
to solve for b
b = -118,206
y = (182/3)x - 118,206
thank you
To find the equation of a line in the form y = mx + b, where m is the slope and b is the y-intercept, you need to follow these steps:
Step 1: Find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Given the points (2004, 3370) and (2007, 3552), we can assign:
x1 = 2004
y1 = 3370
x2 = 2007
y2 = 3552
Substituting these values into the slope formula:
m = (3552 - 3370) / (2007 - 2004)
m = 182 / 3
Therefore, the slope (m) = 182 / 3.
Step 2: Find the y-intercept (b) using the formula:
b = y - mx
You can choose either of the given points to substitute into this formula. Let's use (2004, 3370):
x = 2004
y = 3370
m = 182 / 3
Substituting these values into the y-intercept formula:
b = 3370 - (182 / 3) * 2004
Simplify the equation:
b ≈ 11117.33 or 11117 1/3
Therefore, the y-intercept (b) ≈ 11117.33.
Step 3: Put the slope (m) and y-intercept (b) into the y = mx + b equation:
Now that we have the slope (m) = 182 / 3 and y-intercept (b) ≈ 11117.33, we can write the equation of the line:
y = (182 / 3) * x + 11117.33
So, the equation of the line in y = mx + b form is:
y = (182 / 3) * x + 11117.33