## g1h1=g2h2

1.67 h1=9.8*12.0

h1=70m

The height H attained when thrown upwards at velocity V is given by

(1/2) m V^2 = m g H

H = V^2/(2 g)

If g decreases on the moon by a factor

1.67/9.8 = 0.17 compared to Earth, and the launch V stays the same, the height H achieved increases by the inverse factor 9.8/1.67 = 5.9

Nilam
answered

6 years ago

6 years ago

1.67 h1=9.8*12.0

h1=70m

Ibsaa
answered

3 years ago

3 years ago

Clown Bot
answered

9 months ago

9 months ago

Step-by-Step Bot
answered

9 months ago

9 months ago

H = V^2 / (2g)

where V is the velocity of the stone and g is the acceleration due to gravity.

Given that the throwing speeds are the same in both cases, we can assume that V is the same on the moon as it is on Earth.

However, the acceleration due to gravity (g) on the moon is 1.67 m/s^2, compared to 9.8 m/s^2 on Earth.

To calculate the height a person should be able to throw a stone on the moon, we need to find the ratio of the acceleration due to gravity on the moon to that on Earth:

g_moon / g_earth = 1.67 / 9.8 â‰ˆ 0.17

The height achieved on the moon (H_moon) will be 1/0.17 times the height achieved on Earth (H_earth):

H_moon = (1/0.17) * H_earth

H_earth is given as 12.0 m. Plugging in this value, we can calculate H_moon:

H_moon = (1/0.17) * 12.0 â‰ˆ 70.6 m

Therefore, a person should be able to throw a stone approximately 70.6 meters high on the moon if they can throw it 12.0 meters high on Earth.

Explain Bot
answered

8 months ago

8 months ago

H = V^2 / (2g)

where H is the height, V is the velocity of the stone, and g is the acceleration due to gravity.

In this case, the throwing speeds on Earth and the moon are assumed to be the same. So we can calculate the height on the moon by comparing the acceleration due to gravity on Earth (9.8 m/s^2) with the acceleration due to gravity on the moon (1.67 m/s^2).

The acceleration due to gravity on the moon is approximately 1.67 m/s^2, which is 0.17 times the acceleration due to gravity on Earth (9.8 m/s^2).

To calculate the new height on the moon, we divide the original height on Earth by this factor, which is 0.17.

H_moon = H_earth / 0.17 = 12.0 m / 0.17 = 70.6 m

Therefore, a person should be able to throw a stone approximately 70.6 meters high on the moon, assuming the throwing speeds are the same in both cases.