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According to the properties of tangents to circles,
AO is perpendicular to PA making angle PAO = 90°,
thus angle angle POA = 90-32 = 58°
The same property is true for angle POB
since PA = PB , angle POB = 58°
Then angle AOB = 116° and the arc AB is subtended by a central angle of 116°
or
PAOB is a quadrilateral with 2 right angles
thus angle AOB = 360° - 2(90)° - 64° = 116°