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## To find the factors of the given polynomials, we can try factoring by substitution. By replacing x^2 with b, we can rewrite the polynomials as follows:

First polynomial: b^2 - x^2 + 16

Second polynomial: b^2 - 7x^2y^2 + 9y^4

Now, let's factor the polynomials using the substitution:

First polynomial:

b^2 - x^2 + 16

= b^2 - (b^2) + 16

= 16

So, the first polynomial, x^4 - x^2 + 16, can be factored as 16.

Second polynomial:

b^2 - 7x^2y^2 + 9y^4

= b^2 - 7(b^2)(y^2) + 9y^4

= (b - 3y^2)(b - 3y^2)

Therefore, the second polynomial, x^4 - 7x^2y^2 + 9y^4, can be factored as (x^2 - 3y^2)^2.

In summary, the factors of the given polynomials are:

- For x^4 - x^2 + 16: 16

- For x^4 - 7x^2y^2 + 9y^4: (x^2 - 3y^2)^2