I have 3 questions.
Multiply the polynomials.
-2r(8r+5)
a. -16r^2 + 5
b. -16r^2 + 10
c. -16r^2- 10r
d. -16r^2 - 10
^2a(a^2 + 4a)
a. 2a^2 + 6a^2
b. 2a^3 + 8a^2
c. 2a + 6a
d. 2a^3 + 6a^2
(3y)(3y-2)
a. 9y^2 - 6
b. 9y^2 + 5y
c. 9y^2 + 1
d. 9y^2 - 6y
what are the answers????????????????????
no ideas on any of the? Review the distributive property
-2r(8r+5)
(-2r)(8) + (-2r)(5)
-16r^2 - 10r
Do the others the same way
To multiply the polynomials, follow these steps:
1. For the first polynomial, -2r, distribute -2r to each term of the second polynomial, 8r+5.
-2r * 8r = -16r^2
-2r * 5 = -10r
2. Combine the multiplied terms from step 1 to get the final result.
-16r^2 - 10r
Therefore, for the first question, the correct answer is (d) -16r^2 - 10r.
Now let's move on to the second question.
1. For the polynomial ^2a, multiply each term by the terms in (a^2 + 4a).
^2a * a^2 = 2a^3
^2a * 4a = 8a^2
2. Combine the multiplied terms from step 1 to get the final result.
2a^3 + 8a^2
Therefore, for the second question, the correct answer is (b) 2a^3 + 8a^2.
Finally, let's solve the third question.
1. For the first polynomial, 3y, distribute 3y to each term of the second polynomial, 3y-2.
3y * 3y = 9y^2
3y * -2 = -6y
2. Combine the multiplied terms from step 1 to get the final result.
9y^2 - 6y
Therefore, for the third question, the correct answer is (a) 9y^2 - 6y.
I hope this helps! If you have any more questions, feel free to ask.
To multiply the polynomials, you need to use the distributive property of multiplication over addition. This means that you need to distribute the -2r to both terms inside the parentheses in the first question, ^2a to both terms inside the parentheses in the second question, and 3y to both terms inside the parentheses in the third question.
For the first question, -2r(8r + 5), you distribute -2r to both terms inside the parentheses:
-2r * 8r = -16r^2
-2r * 5 = -10r
So the multiplication of the polynomials is -16r^2 - 10r.
Option d. -16r^2 - 10 is the correct answer for the first question.
For the second question, ^2a(a^2 + 4a), you distribute ^2a to both terms inside the parentheses:
^2a * a^2 = 2a^3
^2a * 4a = 8a^2
So the multiplication of the polynomials is 2a^3 + 8a^2.
Option b. 2a^3 + 8a^2 is the correct answer for the second question.
For the third question, (3y)(3y - 2), you distribute 3y to both terms inside the parentheses:
3y * 3y = 9y^2
3y * -2 = -6y
So the multiplication of the polynomials is 9y^2 - 6y.
Option a. 9y^2 - 6 is the correct answer for the third question.