A piece of stainless steel (Sstainless steel = 0.50 j/g* C) is transferred from an oven (180 *C) to 125mL of water in an insulated container at 23.2 *C. The water temperature rises to 51.5 *C. What is the mass of the stainless steel?
[mass steel x specific heat steel x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] \ 0
Subsitute and solve for the unknown.
To find the mass of the stainless steel, we can use the heat transfer equation:
q = m * c * ΔT
Where:
q is the heat transferred
m is the mass
c is the specific heat capacity
ΔT is the change in temperature
We need to find the mass, so we rearrange the equation:
m = q / (c * ΔT)
Now we can substitute the given values into the equation:
c (specific heat capacity of stainless steel) = 0.50 J/g°C
Initial temperature of the stainless steel = 180°C
Final temperature of the stainless steel = Temperature of the water after transfer = 51.5°C
Initial temperature of the water = 23.2°C
Final temperature of the water = 51.5°C
We need to calculate the heat transferred (q) from the stainless steel to the water. The equation for heat transfer is:
q = m * c * ΔT
For the stainless steel, ΔT = Final temperature of the stainless steel - Initial temperature of the stainless steel:
ΔT = 51.5°C - 180°C
For the water, ΔT = Final temperature of the water - Initial temperature of the water:
ΔT = 51.5°C - 23.2°C
We can calculate the heat transferred (q) using the equation:
q = (mass of stainless steel) * c (specific heat capacity of stainless steel) * (ΔT of stainless steel)
q = (125 mL of water) * (density of water) * c (specific heat capacity of water) * (ΔT of water)
We can then calculate the mass of the stainless steel using the equation:
m = q / (c * ΔT)
Substituting the values, we get:
m = q / (c * ΔT)
Now we can calculate the answer.