a car moving with an initial velocity of 24m/s comes to a hault in 6s .calulate the distance travelled by the car as it comes to rest
the acceleration was (-24m/s)/6s = -4m/s^2
s = vt - 1/2 at^2
= 24*6 - 2*6^2 = 144-72 = 72 m
To calculate the distance traveled by the car as it comes to a halt, we can use the equation for motion with constant acceleration:
\[s = ut + \frac{1}{2}at^2\]
Where:
s = distance traveled
u = initial velocity
t= time taken
a = acceleration
In this case, the initial velocity (u) is 24 m/s and the final velocity is 0 m/s (since the car comes to a halt). The time taken (t) is 6 seconds.
Using these values, we can plug them into the equation to find the distance traveled (s):
\[s = 24 * 6 + \frac{1}{2} * 0 * (6^2)\]
Simplifying the equation:
\[s = 144 + 0\]
Therefore, the distance traveled by the car as it comes to a halt is 144 meters.